Method 1 Converting to Vertex Form Vertex form can be represented as #y=(xh)^2k# where the point #(h,k)# is the vertex To do that, we should complete the square #y=x^22x2# First, we should try to change the last number in a way so we can factor the entire thing #=># we should aim for #y=x^22x1# to make it look like #y=(x1)^2# Complete the square to rewrite the quadratic function in vertex form y = x ^ 2 2x 8 Answers 3 Get Other questions on the subject Mathematics Mathematics, 1530, southerntouch103 Gretchen is setting up for a banquet she has 300 chairs and needs to distribute them evenly among t tables how many chairs should she put atLearn to complete the square in order to write quadratic equations in vertex form Click Create Assignment to assign this modality to your LMS We have a new and improved read on this topic
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Y=x^2+2x-8 in vertex form
Y=x^2+2x-8 in vertex form-Create your account View this answer The given equation is y =x2−2x−8 y = x 2 − 2 x − 8 To convert this into the vertex form, we have to complete the squares Adding 8 8 on both sidesPlug (1,7) into the equation and define b in terms of a math7=ab8\\b=a1/math (0,8) is a point on the parabola, so by symmetry, (2,8) is also a point Plug (2,8) into the equation and define b in terms of a math8=4a2b8\\b=2a\\/math
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Divide 22\sqrt {y} by 2 The equation is now solved Swap sides so that all variable terms are on the left hand side Factor x^ {2}2x1 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2} Take the square root of1) y=(x−17)(x2) 2)y=(x−17)(x−2) 3)y=(x−6)2 2 4) y=(x−6)2 −2 6 Which equation and ordered pair represent the correct vertex form and vertex for j(x) =x2 −12x7?My initial idea was to take the derivative, and set it to zero y = x^2 8x 10 dy/dx = 2x 8 Setting that to zero gives an x value of 4, and plugging x = 4 into the first equation gives y = 6 Thus, the ve
Subtract y from both sides 2x^ {2}8x1y=0 2 x 2 8 x 1 − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 2 for a, 8 for b, and 1y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation is in standard form a x 2 b x c = 0X 2 2x 8 = 0 Step 2 Parabola, Finding the Vertex 21 Find the Vertex of y = x 22x8 Parabolas have a highest or a lowest point called the Vertex Our parabola opens up and accordingly has a lowest point (AKA absolute minimum)Y=x^2−16x63 The vertex has an xvalue of b/2a=(16)/2=8 f(8)= 1 Therefore, the vertex is at (8,1) The vertex form is (xh)^2 k, where you change the sign of the x value of the vertex (h) and keep the y component (k)
Y = x2 − 2x − 8 y = x 2 2 x 8 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 2 x − 8 x 2 2 x 8 Tap for more steps Use the form a x 2 b xFree factor calculator Factor quadratic equations stepbystepYou can put this solution on YOUR website!
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Statistics Arithmetic Mean Geometric Mean Quadratic Mean Median Mode Order Minimum Maximum Probability MidRange Range Standard Deviation Variance Lower Quartile Upper Quartile Interquartile Range Midhinge Standard Normal Distribution PhysicsIs it ellipse 2 Find the coordinates of the vertex and the equation of the axis of symmetry for the parabola represented by x^2 4x 6y 10 = 0 vertex (2 , 1) axis of Math For each situation first write and equation in the form of y=mx bSolved by pluggable solver Completing the Square to Get a Quadratic into Vertex Form Start with the given equation Subtract from both sides Factor out the leading coefficient Take half of the x coefficient to get (ie ) Now square to get (ie ) Now add and
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Click here 👆 to get an answer to your question ️ Express the function y = 2x^2 8x 1 in vertex form Explanation y = x2 − 2x 8 or y = (x2 − 2x 1) −1 8 or y = (x − 1)2 7 Comparing with vertex form of equation f (x) = a(x −h)2 k;(h,k) being vertex we find here h = 1,k = 7,a = 1 ∴ Vertex is at (1,7) and vertex form of equation is y = (x − 1)2 7 graph {x^22x8 3554, 3558, 1778, 1778} Ans Answer link Explanation Changing a quadratic function from standard form to vertex form actually requires that we go through the process of completing the square To do this, we need the x2 and x terms only on the right side of the equation y = x2 2x −8 y 8 = x2 2x −8 8 y 8 = x2 2x −8 8 y 8 = x2 2x
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The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}2xy8=0 x 2 2 x − y − 8 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 2 for b, and 8y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}Find the Vertex Form y=x^22x1 Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formula Simplify the right side Tap for more steps Cancel the common factor ofY = (x 2 2x 8) y = (x 2 2 ⋅ x ⋅1 1 218) y = ((x1) 29) y = (x1) 2 9 By comparing this with the vertex form of parabola, we get (h, k) ==> (1, 9) Example 6 y = (x1)(x3) Solution y = x 24x3 y = x 22 ⋅ x ⋅2 2 22 2 3 y = (x2) 243 y = (x2) 21 By comparing this with the vertex form of parabola, we get
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👉 Learn how to graph quadratic equations by completing the square A quadratic equation is an equation of the form y = ax^2 bx c, where a, b and c are c y = x² 4x 12 When y = 0 x² 4x 12 = 0 x² 4x 12 = 0 (x 2)(x 6) = 0 x = 2 or x = 6 The xintercepts are 2 and 6 y = (x² 4x) 12 y = (x² Find the vertex of the function y = –x2 2x 8 It is where the derivative 2x 2 = 0 Since you probably haven't learned about derivatives, do it this way Rewrite is as x^2 2x 8 = (x1)^2 7 Now look at the form of the formula on the right It
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