dy/dx=(2x)/(3y^21) y^3y=x^2 By differentiating wrt x, Rightarrow 3y^2 dy/dx dy/dx=2x By factoring out dy/dx, Rightarrow (3y^21) dy/dx=2x By dividing both sides by (3y^21), Rightarrow dy/dx=(2x)/(3y^21) I hope that this was clear2 ( y 2 − x y) d x x 2 d y = 0 Need step by step answer Thank you in advance for your help ordinarydifferentialequations derivatives Share edited Mar 8 '14 at 2230 doraemonpaul 151k 3Solution for Solve dy/dx=2xy/(x^2y^2) Q A group of 150 tourists planned to visit East AfricaAmong them, 3 fall ill and did not come, of th A Consider the provided question, First draw the Venn diagram according to the given question, Let K r

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Solution of the differential equation (dy/dx)(3x2y5/2x3y5)=0 is (A) 3x2 4xy 3y2 10x 10y = k (B) x2 4xy y2 4x 6y = k (xSPECIAL CASE #2 A firstorder differential equation of the form y'=f (axbyc) where b0, can always be reduced to a separable firstorder equation by means of the substitution v=axbyc Example y'=1/ (xy1) Solution If we let v=xy1, then dv/dx=1dy/dx, so the differential equation is transformed into (dv/dx)1=1/v or dv/dx= (1v)/v, soQuestion From – Cengage BM Sharma MECHANICS 1 BASIC MATHEMATICS JEE Main, JEE Advanced, NEET, KVPY, AIIMS, CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXTIf `
Start your free trial In partnership with You are being redirected to Course Hero I want to submit the same problem to Course Hero CancelI've gotten to the point where i have (5((3x^2) 5)^4)(4(x2)^3)(6x), what do i do next?We have D (xy^2) = 2x Integrate each side with respect to x to get xy^2 = x^2 C (constant of integration) We will assume we are on the interval (0, infinity) here, so x > 0 Divide by x to get y^2 =x C/x, which gives an implicit form of the general solution on (0, infinity) This is
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Given y = 2x^2 3x 2 find dy/dx To get dy/dx from a formula y in terms of x we must differentiate y with respect to x Generic formula for term differentiation d/dx (ax^b) = bax^b1 = times the coefficient by the power and minus the power by one Applying to each term in the formula gives us dy/dx = 4x 3 Answered by Alex O • Maths tutor 5137 ViewsThe derivative of y with respect to t of `y=2x^25x` at x=3 with `(dx)/(dt)=2` is 14 This result can be interpreted as follows let p be a point on the parabola given by `y=2x^25x`Find dz/dx, dz/dy where x^3 y^3 z^2 3xy^2 z = 3 Answer dz/dx = 3 (y^2 z x^2)/y^2 (2yz 3x), dz/dy = 3z (yz 2x)/y (2yz 3x) Get more help from Chegg



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Ydy F x 1 dx 1 F x 2 dx 2 =0 then set all the differentials except the ones in question equal to zero (ie set dx 2 =0)which leaves F ydy F x1 dx 1 =0 or F ydy = −F x 1 dx 1 dividing both sides by F y and dx =3x2 2xy 4y3 Answer dy dx = − We have dy dx 3x2y = 6x2 We have d y d x 3 x 2 y = 6 x 2 Then I = e∫ 3x2dx = ex3 Then I = e ∫ 3 x 2 d x = e x 3 Multiply through by I ex3 dy dx 3x2ex3 y derivative of ex3 y = 6x2ex3 Multiply through by I e x 3 d y d x 3 x 2 e x 3 y ⏟ derivative of e x 3 y = 6 x 2 e x 3Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!




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The nice thing about this differential equation is that the dy dx is already isolated, therefore the answer can be obtained by simply integrating both sides ∫dy = ∫3x 2 x2 dx y = 3 2x2 −2x−1 C y = 3 2x2 − 2 x C 2 = 3 2 (1)2 − 2 1 C 4 − 3 2 = C 5 2 = CCalculus Find dy/dx y=3x^2 y = 3x2 y = 3 x 2 Differentiate both sides of the equation d dx (y) = d dx (3x2) d d x ( y) = d d x ( 3 x 2) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more stepsMove all terms containing d to the left, all other terms to the right Factor out the Greatest Common Factor (GCF), 'dy' dy(3x 2 3y 2) = 0 Subproblem 1 Set the factor 'dy' equal to zero and attempt to solve Simplifying dy = 0 Solving dy = 0 Move all terms containing d to the left, all other terms to the right




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Separabledifferentialequationcalculator x\frac{dy}{dx}=y^{2} en Related Symbolab blog posts Advanced Math Solutions – Ordinary Differential Equations Calculator, Linear ODE Ordinary differential equations can be a little tricky In a previous post, we talked about a brief overview of How do you find the coordinates of the stationary points to this implicit differentiation equation? Question From – Cengage BM Sharma MECHANICS 1 BASIC MATHEMATICS JEE Main, JEE Advanced, NEET, KVPY, AIIMS, CBSE, RBSE, UP,




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If y = (((3x^2) 5)^5)((x2)^4), then dy/dx = ? Transcript Ex 96, 2 For each of the differential equation , find the general solution 𝑑𝑦𝑑𝑥3𝑦= 𝑒−2𝑥 𝑑𝑦𝑑𝑥3𝑦= 𝑒−2𝑥 Step 1 Put in form 𝑑𝑦𝑑𝑥 Py = Q 𝑑𝑦𝑑𝑥 3y = 𝑒−2𝑥 Step 2 Find P and Q by comparing, we get 𝑃=3 and QGiven differential equation is y"=1 (y')^2,where y'=dy/dx and y"=d^2y/dx^2 Put y'=p so that p'=1p^2 =>dp/ (1p^2)=dx Variables are separableIntegrating both the sides we get tan^1 (p)=xA Given differential equation is y"=1 (y')^2,where y'=dy/dx and y"=d^2y/dx^2



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X^2y = y^2 2x 2xy x^2yy' = 2yy' 2 y'(x^2y2y) = 22xy y' = 2(1xy) y(x^22) math 3x^22xyy^2=2 then the value of dy/dx at x=1 is?Answer to 1 If 3x^22xyy^2=2 then the value of \frac{dy}{dx} x = 1 is \\ A 2 \\ B 0 \\ C 2 \\ D 4 \\ E not defined By signing up, you'llSolve () 2 (6x y )dx y 2x 3y dy 0 − = A 3x 22xyy 2 =C C 3x 22x 2 yy 2 =C B x 23xy2y 2 =C D 3x 2y 3 xy 2 =C * Solve () 2 2 (2xy 3x )dx x y dy 0 − = A 3x 22y 3y 2 =C C 3x 22x 2y 3 =C B 2x 2 y2x 3 y 2 =C * D x 2y 2 3xy 2 =C 21 Find the particular solution of xyy'=1y 2, when x=2 and y=3 A 2y 2




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View this answer Given 2xy dx(x2−1) dy = 0 2 x y d x ( x 2 − 1) d y = 0 Rewrite 2xy dxx2 dy−1 dy = 0 2 x y d x x 2 d y − 1 d y = 0 Change the sides $$2 xy \ dx x^2 \ dy = 1A 10/3 B 0 C 2 D 10/3 E UndefinedClick here👆to get an answer to your question ️ Solve (x^3 3xy^2) dx (y^3 3x^2y)dy = 0



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VITEEE 19 If y=tan1 (4x/15x2)tan1 (23x/32x), then (dy/dx)= (A) (1/125x2)(2/1x2) (B) (2/125x2)(2/1x2) (5/125x2) (D) (1/125x2) Che Find dy/dx (x) 1/2 (y) 1/2 = (a) 1/2 Mention each and every step If y = tan 1 a/x log (xa/xa) 1/2 , prove that dy/dx = 2a 3 /(x 4 – a 4 ) Mention each and every step Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day(quiz problem, (Sec 26 Problem 3)) Determine if the following equation is exact Find the solution if it is exact (3x2 −2xy 2)dx(6y2 −x2 3)dy = 0 Solution Let M(x,y) = 3x2 − 2xy 2 and N(x,y) = 6y2 − x2 3 We have M y = −2x and N x = −2x So M y = N x and the given equation is exact Thus there is a function φ(x,y) such




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5 Let f and g be differentiable functions satisfying g 1(a) =2,g(a) =b and f og = i (identity function)then f 1(b) is equal to 1 ½ 2 2 3 2/3 4 ½ calculus If 3x^22xyy2=2 then the value of dy/dx x = 1 is A 2 B 0 C 2 D 4 E not defined 0 0 1,104 asked by Taeyeon 3x^22xyy2=2 6x 2y 2xy' 2yy' = 0 x=1 ==> y=1Solve ( dy(x))/( dx) (3 x^3 4 x y(x)) 2 y(x)^2 4 x^2 y(x) = 0 Let y(x) = 1/4 (3 x^2 v(x)), which gives ( dy(x))/( dx) = 1/4 (6 x ( dv(x))/( dx)) x^2 (3 x^2 v(x)) 1/4 (6 x ( dv(x))/( dx)) (3 x^3 x (3 x^2 v(x))) 1/8 (3 x^2 v(x))^2 = 0



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Here we look at doing the same thing but using the "dy/dx" notation (also called Leibniz's notation) instead of limits We start by calling the function "y" y = f(x) 1 Add Δx When x increases by Δx, then y increases by Δy y Δy = f(x Δx) 2 Subtract the Two FormulasSo we get (1/y)(dy/dx) = log(2) 4) We want to find dy/dx, which is on the LHS To get this dy/dx on its own we can multiply both sides by y So we get dy/dx = y log(2) 5) To finish this question we need to sub in for y and then we have an answer for dy/dx Recall y=2 If (x2y)dy/dx=2xy, what is the value of d^2y/dx^2 at the point (3,0)?




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If y = √(ax) √(ax)/√(ax) √(ax), then dy/dx = If y = √((1x)/(1x)), then (1x 2)dy/dx y is equal to If y = 1/(az), then dz/dy = If y = 3at 2 /(1t 3) and x = 3at/(1t 3), then dy/dx is equal to If y = 5 x x 5, then dy/dx is equal to If y = a log x bx 2 x has its extremum value at x = 1 and x = 2, then (a, b) = When solving the differential equation $$ (3x^26xy^2) dx (6x^2y4y^2)dy = 0 $$ I verified that it is an Exact Equation By saying that $$ F_x = 3x^26xy^2\\ F_y = 6x^2y4y^2 dy/dx = dY/dX Therefore, the equation becomes (in X, Y) If l, m are chosen to satisfy In X, Y the equation is homogeneous and of the first degree Put Y = VX Then Separating the variables (X, V) and integrating, where A is an arbitrary constant



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Solving a Single Variable Equation 53 Solve 3x1 = 0 Add 1 to both sides of the equation 3x = 1 Divide both sides of the equation by 3 x = 1/3 = 0333X2y3 (xxy2) dy dx = 0 is not separable, since (x 2y3) y = 3x 2y2, but (x xy ) x = 1 y However, after multiplication by µ(x,y) = 1/(xy3), we get x2y3 xy 3 x(1y2) xy dy dx = 0 Simplify x(y −3 y 1) dy dx = 0 Note that this becomes separable, so it is also exact Using the methods from this section, f(x,y) = Z M dx = 1 2 x2 g(yIf dy/dx = y/x and y(2) = 6, then y = 3x y = 1/2x^2 x 4 y = x 4 y = 3 squareroot 8x^2 y = 2x 2 Get more help from Chegg Solve it with our calculus problem solver and calculator




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If y = tan1 4x/(1 5x2) tan1((2 3x)/(3 2x)), where 0 λ/(1 25x2), then find λMove 2 2 to the left of cos ( 2 x) cos ( 2 x) Differentiate using the Power Rule which states that d d x x n d d x x n is n x n − 1 n x n 1 where n = 1 n = 1 Multiply 2 2 by 1 1 Reform the equation by setting the left side equal to the right side Replace y' y ′ with dy dx d y d x




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